I heard Travis was re-taking the Quantitative Section of the GMAT, so I looked up some sample questions. (HINT - For the answers click and drag across the blank area below each question, like highlighting text)Math multiple choice :
For which n is the remainder largest when the number 817,380 is divided by n?
(A) 4
(B) 5
(C) 6
(D) 8
(E) 9
Answer: The correct answer is (D). 817,380 is divisible by all the numbers in the list except 8. Hence, 8 must give the largest remainder because it is the only one that is not zero. To start, 7,380 is divisible by 5 because it ends in 0. It is divisible by 2 because it is even and by 4 because 80 is divisible by 4. However, it is not divisible by 8 because 380 isn’t. In addition, the sum of its digits is 27, which is divisible by 3 and by 9. Because it is divisible by both 2 and 3, it is also divisible by 6.
Data sufficiency:
If x is an odd integer, is y an odd integer?
(1) The average of x and y is odd.
(2) The average of x, y, and (y + 1) is an integer.
Answer choices:
(A) Statement (1) is, by itself, enough to enable you to answer the question, but statement (2) is not enough.
(B) Statement (1) is not enough, by itself, to answer the question, but statement (2) is enough.
(C) Combining statements (1) and (2) provides enough information to answer the question.
(D) Either statement, by itself, provides enough information to answer the question.
(E) Neither statement contains sufficient data to answer the question.
Answer: The correct answer is (A). Statement (1) alone tells us more than we need to know. Simply knowing that the average of x and y is a whole number is enough to tell us that y is odd, since the only way for the average to be a whole number is for the sum of x and y to be even. Thus, if x is odd, so is y. Statement (2) alone is not sufficient. If y is odd, then y + 1 is even; and if y is even, then y + 1 is odd. In either case, x + y + (y + 1) is the sum of two odds and an even, which must be even. There are many even numbers that are divisible by 3, giving an integer for the average.
Good Luck Travis. Happy Studying :)




